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README.md

@@ -23,23 +23,70 @@ From here you should have all the pokemon data in your mysql schema. Feel free t
 Directions: Write a sql query or sql queries that can answer the following questions
 
 * What are all the types of pokemon that a pokemon can have?
+SELECT name FROM types;
 * What is the name of the pokemon with id 45?
+SELECT name FROM pokemons WHERE Id = 45;
 * How many pokemon are there?
+SELECT COUNT(id) FROM pokemons;
 * How many types are there?
+SELECT COUNT(name) FROM types;
 * How many pokemon have a secondary type?
+SELECT COUNT(id) FROM pokemons WHERE secondary_type IS NOT NULL;
 
 ### Part 3: Joins and Groups
 Directions: Write a sql query or sql queries that can answer the following questions
 
 
 * What is each pokemon's primary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Primary_Type 
+FROM pokemons 
+INNER JOIN types 
+ON pokemons.primary_type = types.id;
+
 * What is Rufflet's secondary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Secondary_Type 
+FROM pokemons 
+INNER JOIN types ON pokemons.secondary_type = types.id 
+WHERE pokemons.name LIKE 'Rufflet';
+//Flying
+
 * What are the names of the pokemon that belong to the trainer with trainerID 303?
+SELECT trainerID, pokemons.name AS 'Pokemon Name' 
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON  pokemon_trainer.pokemon_id = pokemons.id 
+WHERE pokemon_trainer.trainerID 
+LIKE '303';
+
 * How many pokemon have a secondary type `Poison`
+SELECT COUNT(name) AS '#Pokemons With Poison Secondary' FROM pokemons WHERE secondary_type LIKE '7';
+
 * What are all the primary types and how many pokemon have that type?
-* How many pokemon at level 100 does each trainer with at least one level 100 pokemone have? (Hint: your query should not display a trainer
+SELECT COUNT(pokemons.name) AS '# Pokemons', types.name AS 'Primary Type' 
+FROM pokemons
+INNER JOIN types 
+ON pokemons.primary_type = types.id 
+GROUP BY pokemons.primary_type;
+
+* How many pokemon at level 100 does each trainer with at least one level 100 pokemon have? (Hint: your query should not display a trainer)
+
+SELECT DISTINCT(trainers.trainername) AS 'Trainers Name', COUNT(*) AS '# lvl 100 Pokemon' 
+FROM trainers
+INNER JOIN pokemon_trainer 
+ON pokemon_trainer.trainerID = trainers.trainerID 
+WHERE pokelevel > 99 
+GROUP BY pokemon_trainer.trainerID 
+ORDER BY COUNT(*) DESC;
+
 * How many pokemon only belong to one trainer and no other?
 
+SELECT COUNT(*) AS '#People Who Caught This Pokemon', pokemons.name AS "Pokemon"
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON pokemon_trainer.pokemon_id = pokemons.id
+GROUP BY pokemon_id
+HAVING COUNT(*) = 1;
+
 ### Part 4: Final Report
 
 Directions: Write a query that returns the following collumns:
@@ -50,6 +97,30 @@ Directions: Write a query that returns the following collumns:
 
 Sort the data by finding out which trainer has the strongest pokemon so that this will act as a ranking of strongest to weakest trainer. You may interpret strongest in whatever way you want, but you will have to explain your decision.
 
+SELECT 
+DISTINCT(pokemon_trainer.pokemon_id) AS 'Pokemon Name',  
+pokemon_trainer.trainerID AS 'Trainer Name', 
+pokemon_trainer.pokelevel AS 'Level', 
+pokemons.primary_type AS 'Primary Type', 
+pokemons.secondary_type AS 'Secondary Type'  
+FROM pokemon_trainer  
+INNER JOIN pokemons  
+ON pokemon_trainer.pokemon_id = pokemons.id
+ORDER BY pokemon_id DESC
+;
+
+
+SELECT 
+pokemon_trainer.pokemon_id AS 'Pokemon Name',  
+pokemon_trainer.trainerID AS 'Trainer Name', 
+pokemon_trainer.pokelevel AS 'Level', 
+pokemons.primary_type AS 'Primary Type', 
+pokemons.secondary_type AS 'Secondary Type'  
+FROM pokemon_trainer  
+INNER JOIN pokemons  
+ON pokemon_trainer.pokemon_id = pokemons.id;
+
+
 ## Turning in this assignment
 
 To turn in this assignment, create files for each part with at least one query for each question answered. Above each query include a comment with the question you were answering. The files should have the extension `.sql`

answers/Q1.sql

@@ -0,0 +1,2 @@
+#What are all the types of pokemon that a pokemon can have?
+SELECT name FROM types;

answers/Q10.sql

@@ -0,0 +1,6 @@
+#What are all the primary types and how many pokemon have that type?
+SELECT COUNT(pokemons.name) AS '# Pokemons', types.name AS 'Primary Type' 
+FROM pokemons
+INNER JOIN types 
+ON pokemons.primary_type = types.id 
+GROUP BY pokemons.primary_type;

answers/Q11.sql

@@ -0,0 +1,9 @@
+#How many pokemon at level 100 does each trainer with at least one level 100 pokemone have? (Hint: your query should not display a trainer)
+
+SELECT Distinct(trainers.trainername) AS 'Trainers Name', COUNT(*) AS '# lvl 100 Pokemon' 
+FROM trainers
+INNER JOIN pokemon_trainer 
+ON pokemon_trainer.trainerID = trainers.trainerID 
+WHERE pokelevel > 99 
+GROUP BY pokemon_trainer.trainerID 
+ORDER BY COUNT(*) DESC; 

answers/Q12.sql

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+#How many pokemon only belong to one trainer and no other?
+
+SELECT COUNT(pokemon_trainer.trainerID) AS '#People Who Caught This Pokemon', pokemons.name AS "Pokemon"
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON pokemon_trainer.pokemon_id = pokemons.id
+GROUP BY pokemon_id
+HAVING COUNT(pokemon_trainer.trainerID) = 1;

answers/Q13.sql

@@ -0,0 +1,13 @@
+SELECT p.name AS 'Pokemon Name',
+t.trainername AS 'Trainer Name',
+pt.pokelevel AS 'Level',
+t1.name AS 'Primary Type',
+t2.name AS 'Secondary Type'
+FROM pokemon_trainer pt
+JOIN trainers t ON pt.trainerID = t.trainerID
+JOIN pokemons p ON pt.pokemon_id = p.id
+JOIN types t1 ON p.primary_type = t1.id
+JOIN types t2 ON p.secondary_type = t2.id
+ORDER BY (maxhp + attack + defense + spatk + spdef + speed) DESC, pt.pokelevel DESC; 
+
+#The strongest is determined by having the highest of all the stats and having the highest level. 

answers/Q2.sql

@@ -0,0 +1,2 @@
+#What is the name of the pokemon with id 45?
+SELECT name FROM pokemons WHERE Id = 45;

answers/Q3.sql

@@ -0,0 +1,2 @@
+#How many pokemon are there?
+SELECT COUNT(id) FROM pokemons;

answers/Q4.sql

@@ -0,0 +1,2 @@
+#How many types are there?
+SELECT COUNT(name) FROM types;

answers/Q5.sql

@@ -0,0 +1,2 @@
+#How many pokemon have a secondary type?
+SELECT COUNT(id) FROM pokemons WHERE secondary_type IS NOT NULL;

answers/Q6.sql

@@ -0,0 +1,5 @@
+# What is each pokemon's primary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Primary_Type 
+FROM pokemons 
+INNER JOIN types 
+ON pokemons.primary_type = types.id;

answers/Q7.sql

@@ -0,0 +1,6 @@
+# What is Rufflet's secondary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Secondary_Type 
+FROM pokemons 
+INNER JOIN types on pokemons.secondary_type = types.id 
+WHERE pokemons.name 
+LIKE 'Rufflet';

answers/Q8.sql

@@ -0,0 +1,7 @@
+# What are the names of the pokemon that belong to the trainer with trainerID 303?
+SELECT trainerID, pokemons.name AS 'Pokemon Name' 
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON  pokemon_trainer.pokemon_id = pokemons.id 
+WHERE pokemon_trainer.trainerID 
+LIKE '303';

answers/Q9.sql

@@ -0,0 +1,5 @@
+#How many pokemon have a secondary type `Poison`?
+SELECT COUNT(name) AS '#Pokemons With Poison Secondary' 
+FROM pokemons 
+WHERE secondary_type 
+LIKE '7';

answers/answers.txt

@@ -0,0 +1,112 @@
+# MySQL Pokemon Report Queries
+
+### Goals
+* Become proficient selecting data out of a mysql database
+* Become comfortable performing a SQL join
+* Be able to format SQL output as a readable report
+
+## Instructions
+
+### Part 1: Importing data
+Directions:
+
+* In DataGrip, [connect to your local mysql instance](https://www.jetbrains.com/help/idea/connecting-to-a-database.html#mysql)
+**(for those not using DataGrip, you can execute the files in the command line, using the following syntax: ```mysql -u your_mysql_user -p < the_name_of_the_file.sql```)
+* Create your pokemon schema
+* Unpack the pokemon_sql.zip files
+* One by one execute these files making sure to check your pokemon schema
+
+From here you should have all the pokemon data in your mysql schema. Feel free to explore the data and perform a few select statements to see what the data looks like.
+
+### Part 2: Simple Selects and Counts
+
+Directions: Write a sql query or sql queries that can answer the following questions
+
+* What are all the types of pokemon that a pokemon can have?
+SELECT name FROM types;
+* What is the name of the pokemon with id 45?
+SELECT name FROM pokemons WHERE Id = 45;
+* How many pokemon are there?
+SELECT COUNT(id) FROM pokemons;
+* How many types are there?
+SELECT COUNT(name) FROM types;
+* How many pokemon have a secondary type?
+SELECT COUNT(id) FROM pokemons WHERE secondary_type IS NOT NULL;
+
+### Part 3: Joins and Groups
+Directions: Write a sql query or sql queries that can answer the following questions
+
+
+* What is each pokemon's primary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Primary_Type 
+FROM pokemons 
+INNER JOIN types 
+ON pokemons.primary_type = types.id;
+
+* What is Rufflet's secondary type?
+SELECT pokemons.name AS Pokemon_Name, types.name AS Secondary_Type 
+FROM pokemons 
+INNER JOIN types on pokemons.secondary_type = types.id WHERE pokemons.name 
+LIKE 'Rufflet';
+//Flying
+
+* What are the names of the pokemon that belong to the trainer with trainerID 303?
+SELECT trainerID, pokemons.name AS 'Pokemon Name' 
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON  pokemon_trainer.pokemon_id = pokemons.id 
+WHERE pokemon_trainer.trainerID 
+LIKE '303';
+
+* How many pokemon have a secondary type `Poison`
+SELECT COUNT(name) AS '#Pokemons With Poison Secondary' FROM pokemons WHERE secondary_type LIKE '7';
+
+* What are all the primary types and how many pokemon have that type?
+SELECT COUNT(pokemons.name) AS '# Pokemons', types.name AS 'Primary Type' 
+FROM pokemons
+INNER JOIN types 
+ON pokemons.primary_type = types.id 
+GROUP BY pokemons.primary_type;
+
+* How many pokemon at level 100 does each trainer with at least one level 100 pokemone have? (Hint: your query should not display a trainer)
+
+SELECT Distinct(trainers.trainername) AS 'Trainers Name', COUNT(*) AS '# lvl 100 Pokemon' 
+FROM trainers
+INNER JOIN pokemon_trainer 
+ON pokemon_trainer.trainerID = trainers.trainerID 
+WHERE pokelevel > 99 
+GROUP BY pokemon_trainer.trainerID 
+ORDER BY COUNT(*) DESC;
+
+* How many pokemon only belong to one trainer and no other?
+
+SELECT COUNT(pokemon_trainer.trainerID) AS '#People Who Caught This Pokemon', pokemons.name AS "Pokemo"
+FROM pokemon_trainer 
+INNER JOIN pokemons
+ON pokemon_trainer.pokemon_id = pokemons.id
+GROUP BY pokemon_id
+HAVING COUNT(pokemon_trainer.trainerID) = 1;
+
+### Part 4: Final Report
+
+Directions: Write a query that returns the following collumns:
+
+| Pokemon Name | Trainer Name | Level | Primary Type | Secondary Type |
+|:------------:|:------------:|:-----:|:------------:|:--------------:|
+| Pokemon's name| Trainer's name| Current Level| Primary Type Name| Secondary Type Name|
+
+Sort the data by finding out which trainer has the strongest pokemon so that this will act as a ranking of strongest to weakest trainer. You may interpret strongest in whatever way you want, but you will have to explain your decision.
+
+## Turning in this assignment
+
+To turn in this assignment, create files for each part with at least one query for each question answered. Above each query include a comment with the question you were answering. The files should have the extension `.sql`
+Example: 
+
+```SQL
+ # How many characters are in the string 'Hello World!'
+ SELECT CHAR_LENGTH('Hello World!') AS length_of_hello_world
+```
+
+For Part 4 specifically also leave a comment explaining how your query is deciding who the strongest trainer is
+
+Once all of that is done, submit your file by saving it in the "answers" directory and commititing it to your fork.