Complete

Part 2.sql

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+# Question: What are all the types of pokemon that a pokemon can have?
+# Answer: Normal, Water, Grass, Rock, Fire, Ground, Poison, Bug, Electric, Dragon, Steel, Dark, Fighting, Psychic, Ghost, Fairy, Ice, Flying
+SELECT GROUP_CONCAT(' ', name)
+FROM types;
+
+# Question: What is the name of the pokemon with id 45?
+# Answer: Eevee
+SELECT name
+FROM pokemons
+WHERE id = 45;
+
+# Question: How many pokemon are there?
+# Answer: 656
+SELECT COUNT(1)
+FROM pokemons;
+
+# Question: How many types are there?
+# Answer: 18
+SELECT COUNT(1)
+FROM types;
+
+# Question: How many pokemon have a secondary type?
+# Answer: 316
+SELECT COUNT(secondary_type)
+FROM pokemons;

Part3.sql

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+# Question: What is each pokemon's primary type?
+# Answer: Omitted for brevity
+SELECT p.name, t.name
+FROM pokemons p
+JOIN types t
+ON p.primary_type = t.id;
+
+# Question: What is Rufflet's secondary type?
+# Answer: Flying
+SELECT t.name
+FROM pokemons p
+JOIN types t
+ON p.secondary_type = t.id
+WHERE p.name = 'Rufflet';
+
+# Question: What are the names of the pokemon that belong to the trainer with trainerID 303?
+# Answer: Wailord & Vileplume
+SELECT p.name
+FROM pokemon_trainer pt
+JOIN pokemons p
+ON pt.pokemon_id = p.id
+WHERE pt.trainerID = 303;
+
+# Question: How many pokemon have a secondary type Poison
+# Answer: 31
+SELECT COUNT(1)
+FROM pokemons p
+JOIN types t
+ON p.secondary_type = t.id
+WHERE t.name = 'Poison';
+
+# Question: What are all the primary types and how many pokemon have that type?
+# Answer: Omitted for brevity
+SELECT t.name, COUNT(1)
+FROM pokemons p
+JOIN types t
+ON p.primary_type = t.id
+GROUP BY t.name;
+
+# Question: How many pokemon at level 100 does each trainer with at least one level 100 pokemone have?
+# Answer: Omitted for brevity
+SELECT trainerID, COUNT(1)
+FROM pokemon_trainer
+WHERE pokelevel = 100
+GROUP BY trainerID;
+
+# Question: How many pokemon only belong to one trainer and no other?
+# Answer: 13
+SELECT COUNT(pokemon_id)
+FROM (
+    SELECT pokemon_id
+    FROM pokemon_trainer
+    GROUP BY pokemon_id
+    HAVING COUNT(*) = 1
+) AS ONE_OCCURRENCE

Part4.sql

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+# Part 4: Final Report
+# Explanation: Since pokelevel directly influences the fields HP, max HP, attack, defense, etc.,
+    # I thought the best way to order the trainers would be take an average of the totals of these fields
+    # for each of their pokemon. The "best" trainer will have pokemon with the highest average in these fields.
+
+SELECT DISTINCT GROUP_CONCAT(p.name) as "Pokemon", tr.trainername as "Trainer",
+       GROUP_CONCAT(pt.pokelevel) as "PokeLevels", GROUP_CONCAT(t.name) as "Primary Types",
+       GROUP_CONCAT(r.name) as "Secondary Types", AVG_POINTS.total
+FROM pokemon_trainer pt
+JOIN (
+         SELECT trainerID, AVG(hp + maxhp + attack + defense + spatk + spdef + speed) as total
+         FROM pokemon_trainer
+         GROUP BY trainerID
+) AS AVG_POINTS ON AVG_POINTS.trainerID = pt.trainerID
+JOIN pokemons p ON p.id = pt.pokemon_id
+JOIN trainers tr ON tr.trainerID = pt.trainerID
+JOIN types t ON t.id = p.primary_type
+JOIN types r ON r.id = p.secondary_type
+GROUP BY AVG_POINTS.total, tr.trainerID, tr.trainername
+ORDER BY AVG_POINTS.total DESC
+LIMIT 20;