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38 changes: 38 additions & 0 deletions course-schedule/ys-han00.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,38 @@
class Solution {
public:
bool canFinish(int numCourses, vector<vector<int>>& prerequisites) {
int visited = 0;
vector<vector<int>> outdegree(numCourses, vector<int>());
vector<int> indegree(numCourses, 0);

for(auto edge : prerequisites) {
outdegree[edge[0]].push_back(edge[1]);
indegree[edge[1]]++;
}

queue<int> que;
for(int i = 0; i < numCourses; i++) {
if(indegree[i] == 0) {
que.push(i);
visited++;
}
}


while(!que.empty()) {
int now = que.front();
que.pop();

for(auto next : outdegree[now]) {
indegree[next]--;
if(indegree[next] == 0) {
visited++;
que.push(next);
}
}
}

return (visited == numCourses ? true : false);
}
};

33 changes: 33 additions & 0 deletions invert-binary-tree/ys-han00.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,33 @@
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
queue<TreeNode*> que;
que.push(root);

while(!que.empty()) {
Comment on lines +15 to +18
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저는 dfs 를 사용했었는데 bfs도 활용할 수 있겠네요! null 처리도 가독성 좋게 구현된 것 같습니다

TreeNode *curr = que.front();
que.pop();

if(!curr)
continue;

swap(curr->left, curr->right);
que.push(curr->left);
que.push(curr->right);
}

return root;
}
};

34 changes: 34 additions & 0 deletions jump-game/ys-han00.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,34 @@
// class Solution {
// public:
// bool canJump(vector<int>& nums) {
// int n = nums.size();
// vector<bool> dp(n);

// dp[n - 1] = true;
// for(int i = n - 2; i >= 0; i--) {
// for(int j = min(n - 1, nums[i] + i); i <= j; j--) {
// if(dp[j]) {
// dp[i] = true;
// break;
// }
// }
// }

// return dp[0];
// }
// };

class Solution {
public:
bool canJump(vector<int>& nums) {
int maxPos = 0;
for(int i = 0; i < nums.size(); i++) {
if(maxPos < i)
return false;
maxPos = max(maxPos, i + nums[i]);
}

return true;
}
};

68 changes: 68 additions & 0 deletions merge-k-sorted-lists/ys-han00.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,68 @@
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
// class Solution {
// public:
// ListNode* mergeKLists(vector<ListNode*>& lists) {
// vector<int> nums;
// for(ListNode* list : lists) {
// while(list != nullptr) {
// nums.push_back(list->val);
// list = list->next;
// }
// }

// if(nums.size() == 0)
// return nullptr;

// sort(nums.begin(), nums.end());
// ListNode* root = new ListNode(nums[0]);
// ListNode* curr = root;

// for(int i = 1; i < nums.size(); i++) {
// curr->next = new ListNode(nums[i]);
// curr = curr->next;
// }

// return root;
// }
// };

class Solution {
public:
ListNode* mergeKLists(vector<ListNode*>& lists) {
priority_queue<
pair<int, int>,
vector<pair<int, int>>,
greater<pair<int, int>>
> pq;

for(int i = 0; i < lists.size(); i++)
if(lists[i])
pq.push({lists[i]->val, i});

ListNode dummy(-1);
ListNode* curr = &dummy;
while(!pq.empty()) {
auto [val, idx] = pq.top();
pq.pop();

curr->next = new ListNode(val);
curr = curr->next;

lists[idx] = lists[idx]->next;
if(lists[idx])
pq.push({lists[idx]->val, idx});
}

return dummy.next;
}
};

29 changes: 29 additions & 0 deletions search-in-rotated-sorted-array/ys-han00.cpp
Original file line number Diff line number Diff line change
@@ -0,0 +1,29 @@
class Solution {
public:
int search(vector<int>& nums, int target) {
int left = 0, right = nums.size() - 1, mid;

while(left <= right) {
mid = (left + right) / 2;

if(target == nums[mid])
return mid;

if(nums[left] <= nums[mid]) {
if(nums[left] <= target && target < nums[mid])
right = mid - 1;
else
left = mid + 1;
}
else {
if(nums[mid] < target && target <= nums[right])
left = mid + 1;
else
right = mid - 1;
}
}

return -1;
}
};